laravel join关联查询
1、两表关联
$fbaInventoryTb = (new \App\Model\Amz\Fba\InventoryReport)->getTable(); $productTb = (new \App\Model\Amz\Product)->getTable(); $twInventoryTb = (new \App\Model\TWUsa\TwusaInventory)->getTable(); $qry = \DB::table($fbaInventoryTb); $qry->select($fbaInventoryTb.'.*') ->where($fbaInventoryTb.'.ec_id',1) ->leftjoin($productTb, $productTb.'.sku', '=', $fbaInventoryTb.'.sku') ->addSelect($productTb.'.id as goods_id',$productTb.'.sku as mfn', $productTb.'.ec_id as pro_ec_id'); // ->where($productTb.'.ec_id',1); //不该该在此处解除 product 表的ec_id // return $qry->toSql(); $res = $qry->get()->whereIn('pro_ec_id',[1, null] );//leftJion 最后解除不切合条件的
2、三表关联
$qry = \DB::table($twInventoryTb); $qry->select($twInventoryTb.'.*') ->leftjoin($fbaInventoryTb, $fbaInventoryTb.'.fnsku', '=', $twInventoryTb.'.product_sn') ->addSelect($fbaInventoryTb.'.ec_id') ->where($fbaInventoryTb.'.ec_id',1); $qry->LeftJoin($productTb, $productTb.'.sku', '=', $fbaInventoryTb.'.sku') // ->where($productTb.'.ec_id',1) ->addSelect($productTb.'.id as goods_id', $productTb.'.sku as mfn', $productTb.'.ec_id as pro_ec_id'); $res = $qry->get()->whereIn('pro_ec_id', [1, null]);
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