Laravel find in set排序实例

做项目遇到个需求,需要对结果集中的数据进行指定规则的顺序排列。

例如,用户状态有四种:

=>未激活;1=>正常;2=>禁用;3=>软删除

现在的需求是,我要按照:正常->未激活->禁用->删除;这个顺序来进行排序,同时按照注册时间降序,网上查了很多资料,国内提到这个的很少,在stackOverFlow上找到了答案!

先上解决方案:

public function index($customer_type = null) {
  $search = request('search');
  $perPage = request('perPage') ? request('perPage') : 10;
  $customer_type = $customer_type ? $customer_type : request('customer_type');
  // \DB::enableQueryLog();
  $data = Customer::select(['id', 'email', 'user_name', 'nick_name', 'status', 'phone', 'create_time'])
    ->where('customer_type', '=', $customer_type)
    ->where(function ($query) use ($search) {
      if ($search) {
        $query->where('user_name', 'like binary', '%' . $search . '%')
          ->orWhere('nick_name', 'like binary', '%' . $search . '%')
          ->orWhere('phone', 'like binary', '%' . $search . '%')
          ->orWhere('email', 'like binary', '%' . $search . '%');
      }
    })
    ->orderByRaw("FIELD(status, " . implode(", ", [1, 2, 0, 3, 4]) . ")")
    ->orderBy('create_time', 'desc')
    ->paginate($perPage);
  // $query = \DB::getQueryLog();
  // dd($data);
  //追加额外参数,例如搜索条件
  $appendData = $data->appends(array(
    'search' => $search,
    'perPage' => $perPage,
  ));
  return view('admin/customer/customerList', compact('data'));
}

打印出来的sql语句如下:

array:2 [▼
 => array:3 [▼
“query” => “select count(*) as aggregate from customer where customer_type = ?”
“bindings” => array:1 [▼
 => “1”
]
“time” => 2.08
]
 => array:3 [▼
“query” => “select id, email, user_name, nick_name, status, phone, create_time from customer where customer_type = ? order by FIELD(status, 1, 2, 0, 3, 4), create_time desc limit 10 offset 0”
“bindings” => array:1 [▼
 => “1”
]
“time” => 1.2
]
]

参考了以下链接:

https://stackoverflow.com/questions/42068986/laravel-weird-behavior-orderbyrawfield

https://stackoverflow.com/questions/34244455/how-to-use-not-find-in-set-in-laravel-5-1

https://stackoverflow.com/questions/35594450/find-in-set-in-laravel-example/35594503

find_in_set 复杂应用:

public function get_teacher_list($timeType, $name, $perPage = 10, $personality = 0, $teachingStyle = 0, $ageType = 0)
{
  // \DB::enableQueryLog();
  $result_data = DB::table('teacher_info as ti')
    ->select('ti.*')
    ->join('customer', 'customer.id', '=', 'ti.customer_id')
    ->where(function ($query) use ($personality) {
      if (trim($personality)) {
        $query->whereRaw("find_in_set($personality,ti.label_ids)");
      }
    })
    ->where(function ($query) use ($teachingStyle) {
      if (trim($teachingStyle)) {
        $query->whereRaw("find_in_set($teachingStyle,ti.label_ids)");
      }
    })
    ->where(function ($query) use ($ageType) {
      if (trim($ageType)) {
        $ageType = explode('-', $ageType);
        $query->whereRaw("DATE_FORMAT(FROM_DAYS(TO_DAYS(NOW())-TO_DAYS(birthday)), '%Y')+0 between $ageType[0] and $ageType[1]");
      }
    })
    ->where(function ($query) use ($timeType) {
      //1本周,2下周
      if ($timeType == 1) {
        $query->where('ti.can_appointment_1', 1);
      } elseif ($timeType == 2) {
        $query->where('ti.can_appointment_2', 1);
      } else {
        $query->where('ti.can_appointment_1', '>', 0)
          ->orWhere('ti.can_appointment_2', '>', 0);
      }
    })
    ->where(function ($query) use ($name) {
      if (trim($name)) {
        $query->where('ti.chinese_name', 'like', '%' . $name . '%')
          ->orWhere('ti.english_name', 'like', '%' . $name . '%');
      }
    })
    ->where('ti.status', 1)
    ->orderBy('ti.total_teach_num', 'desc')
    ->orderBy('ti.total_star_num', 'desc')
    ->orderBy('ti.satisfaction', 'desc')
    ->orderBy('ti.comment_num', 'desc')
    ->orderBy('ti.english_name', 'asc')
    ->paginate($perPage);
  // dd($result_data, \DB::getQueryLog());

  return $result_data;
}

      

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